Two rods A and B are of equal lengths. Their ends are kept between the same temperatures and their area cross-sections are A₁ and A₂, thermal conductivities are K₁ and K₂. The rate of heat transmission in the two rods will be equal if (a) K₁A₂ = K₂A₁ (b) K₁A₁ = K₂A₂ (c) K₁A₁² = K₂A₂² (d) K₁ = K₂

Answer: (b). H = (KAΔ T)/(L) with the same L and Δ T for both rods. H₁ = H₂ ⇒ K₁A₁ = K₂A₂ So the answer is (b).

Two rods A and B are of equal lengths. Their ends are kept between… | MHT CET 2026 (13 May, Shift 1)

Q2MHT CET 2026 · 13 MAY · SHIFT 1Easy

Heat Conduction

Two rods A and B are of equal lengths. Their ends are kept between the same temperatures and their area cross-sections are $A_1$ and $A_2$ , thermal conductivities are $K_1$ and $K_2$ . The rate of heat transmission in the two rods will be equal if

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Answer: (b)

$H = \frac{KA\Delta T}{L}$ with the same $L$ and $\Delta T$ for both rods.
$H_1 = H_2 \Rightarrow K_1A_1 = K_2A_2$
So the answer is (b).

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Heat Conduction question from MHT CET 2026 (13 May, Shift 1)

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