Two rods of different materials have lengths ' l₁ ' and ' l₂ ' whose coefficient of linear expansions are ' α₁ ' and ' α₂ ' respectively. If the difference between the two lengths is independent of temperature then (a) α₁² l₁ = α₂² l₂ (b) (l₁)/(l₂) = (α₂)/(α₁) (c) (l₁)/(l₂) = (α₁)/(α₂) (d) l₁² α₂ = l₂² α₁

Answer: (b). Difference constant means equal expansions: l₁α₁Δ T=l₂α₂Δ T. (l₁)/(l₂)=(α₂)/(α₁) So the answer is (b).

Two rods of different materials have lengths ' l₁ ' and ' l₂ ' whose… | MHT CET 2025 (19 Apr, Shift 1)

Q20MHT CET 2025 · 19 APR · SHIFT 1Medium

Thermometry & Thermal Expansion

Two rods of different materials have lengths ' $l_1$ ' and ' $l_2$ ' whose coefficient of linear expansions are ' $\alpha_1$ ' and ' $\alpha_2$ ' respectively. If the difference between the two lengths is independent of temperature then

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Answer: (b)

Difference constant means equal expansions: $l_1\alpha_1\Delta T=l_2\alpha_2\Delta T$ .
$\frac{l_1}{l_2}=\frac{\alpha_2}{\alpha_1}$
So the answer is (b).

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Thermometry & Thermal Expansion question from MHT CET 2025 (19 Apr, Shift 1)

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