Two rods of different metals have coefficients of linear expansion ' α₁ ' and ' α₂ ' respectvely. Their respective lengths are ' L₁ ' and ' L₂ '. At all temperatures ( L₂ - L₁) is same. The correct relation is (a) L₁ α₁² = L₂ α₂² (b) L₁² α₁² = L₂² α₂² (c) L₁ α₂ = L₂ α₁ (d) L₁ α₁ = L₂ α₂

Answer: (d). (L₂-L₁) constant means both rods expand by the same amount: L₁α₁Δ T=L₂α₂Δ T. So the answer is (d) L₁α₁=L₂α₂.

Two rods of different metals have coefficients of linear expansion '… | MHT CET 2021 (23 Sep, Shift 1)

Q50MHT CET 2021 · 23 SEP · SHIFT 1Medium

Thermometry & Thermal Expansion

Two rods of different metals have coefficients of linear expansion ' $\alpha_1$ ' and ' $\alpha_2$ ' respectvely. Their respective lengths are ' $\text{L}_1$ ' and ' $\text{L}_2$ '. At all temperatures ( $\text{L}_2 - \text{L}_1$ ) is same. The correct relation is

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Answer: (d)

$(L_2-L_1)$ constant means both rods expand by the same amount: $L_1\alpha_1\Delta T=L_2\alpha_2\Delta T$ .
So the answer is (d) $L_1\alpha_1=L_2\alpha_2$ .

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Thermometry & Thermal Expansion question from MHT CET 2021 (23 Sep, Shift 1)

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