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NEET 2022 (Phase 2) · Heat Conduction

Heat Conduction question from NEET 2022 (Phase 2)

Q28NEET 2022 · PHASE 2Medium

Heat Conduction

Two rods one made of copper and other made of steel of same length and same cross sectional area are joined together. The thermal conductivity of copper and steel are 385 J s−1{}^{-1} K−1{}^{-1} m−1{}^{-1} and 50 J s−1{}^{-1} K−1{}^{-1} m−1{}^{-1} respectively. The free ends of copper and steel are held at 100∘^\circC and 0∘^\circ C respectively. The temperature at the junction is, nearly:

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Answer: (a)

  1. Same heat current in both rods (same LL, AA): 385(100−θ)=50(θ−0)385(100-\theta) = 50(\theta - 0)
  2. 435θ=38500435\theta = 38500
  3. θ≈88.5∘C\theta \approx 88.5^\circ\text{C}, so the answer is (a).
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