Two S.H.Ms. are represented by equations y₁ = 0.1sin (100π t + π/3) and y₂ = 0.1cos (100π t) The phase difference between the speeds of the two particles is (a) π/3 (b) -π/6 (c) +π/6 (d) -π/3

Answer: (b). v₁ = (dy₁)/(dt) ∝ cos (100π t + π/3) v₂ ∝ -sin (100π t) = cos (100π t + π/2) Δφ = π/3 - π/2 = -π/6 So the answer is (b) -π/6.

Two S.H.Ms. are represented by equations y₁ = 0.1sin (100π t + π/3)… | MHT CET 2023 (9 May, Shift 2)

Q35MHT CET 2023 · 9 MAY · SHIFT 2Medium

Periodic Motion & SHM Basics

Two S.H.Ms. are represented by equations $y_1 = 0.1\sin\left(100\pi t + \frac{\pi}{3}\right)$ and $y_2 = 0.1\cos(100\pi t)$ The phase difference between the speeds of the two particles is

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Answer: (b)

$v_1 = \frac{dy_1}{dt} \propto \cos\left(100\pi t + \frac{\pi}{3}\right)$
$v_2 \propto -\sin(100\pi t) = \cos\left(100\pi t + \frac{\pi}{2}\right)$
$\Delta\phi = \frac{\pi}{3} - \frac{\pi}{2} = -\frac{\pi}{6}$
So the answer is (b) $-\frac{\pi}{6}$ .

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Periodic Motion & SHM Basics question from MHT CET 2023 (9 May, Shift 2)

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