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MHT CET 2024 (9 May, Shift 1) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from MHT CET 2024 (9 May, Shift 1)

Q7MHT CET 2024 · 9 MAY · SHIFT 1Medium

Satellite Energy & Weightlessness

Two satellites A and B having ratio of masses 3:13 : 1 are revolving in circular orbits of radii ' rr ' and ' 4 r '. The ratio of total energy of satellites A to that of B is

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Answer: (d)

  1. E=−GMm2rE = -\frac{GMm}{2r}, so E∝mrE \propto \frac{m}{r}.
  2. EAEB=31⋅4rr=12\frac{E_A}{E_B} = \frac{3}{1}\cdot\frac{4r}{r} = 12.
  3. So the answer is (d) 12:112 : 1.
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