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JEE Main 2021 (25 Feb, Shift 1) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2021 (25 Feb, Shift 1)

Q52JEE Main 2021 · 25 FEB · SHIFT 1Difficult

Satellites - Orbital Velocity & Period

Two satellites A and B of masses 200 kg and 400 kg are revolving round the earth at height of 600 km and 1600 km respectively.

If TA and TB are the time periods of A and B respectively then the value of TB −- TA:

Figure

[Given: radius of earth = 6400 km, mass of earth = 6 ×\times 1024 kg]

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Answer: (a)

  1. Orbit radii: rA=6400+600=7000r_A = 6400 + 600 = 7000 km, rB=6400+1600=8000r_B = 6400 + 1600 = 8000 km. T=2πr3GMT = 2\pi\sqrt{\frac{r^3}{GM}} (mass of satellite does not matter).
  2. GM=6.67×10−11×6×1024=4.0×1014GM = 6.67\times10^{-11}\times6\times10^{24} = 4.0\times10^{14} SI
  3. TA=2π3.43×10204.0×1014≈5.82×103T_A = 2\pi\sqrt{\frac{3.43\times10^{20}}{4.0\times10^{14}}} \approx 5.82\times10^3 s, TB=2π5.12×10204.0×1014≈7.11×103T_B = 2\pi\sqrt{\frac{5.12\times10^{20}}{4.0\times10^{14}}} \approx 7.11\times10^3 s
  4. TB−TA≈1.3×103T_B - T_A \approx 1.3\times10^3 s
  5. So the answer is (a) 1.33×1031.33\times10^3 s.
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