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JEE Main 2021 (18 Mar, Shift 1) · Young's Modulus & Elongation

Young's Modulus & Elongation question from JEE Main 2021 (18 Mar, Shift 1)

Q22JEE Main 2021 · 18 MAR · SHIFT 1Medium

Young's Modulus & Elongation

Two separate wires A and B are stretched by 2 mm and 4 mm respectively, when they are subjected to a force of 2 N. Assume that both the wires are made up of same material and the radius of wire B is 4 times that of the radius of wire A. The length of the wires A and B are in the ratio of a: b. Then a/b can be expressed as 1/x where x is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 32

  1. Δl=FLπr2Y\Delta l = \frac{FL}{\pi r^2 Y}, so with same FF and YY: L∝Δl r2L \propto \Delta l \, r^2
  2. LALB=24×(rA4rA)2=12×116=132\frac{L_A}{L_B} = \frac{2}{4} \times \left(\frac{r_A}{4r_A}\right)^2 = \frac{1}{2} \times \frac{1}{16} = \frac{1}{32}
  3. So x=32x = 32.
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