Two simple harmonic progressive waves have displacements y₁ = 5sin ((2π x)/(λ) - ω t) and y₂ = 5cos ((2π x)/(λ) - ω t + π/6). The phase difference between the two waves is (a) π/3 (b) π/6 (c) 2π/3 (d) 3π/2

Answer: (c). Let θ = (2π x)/(λ) - ω t. Then y₁ = 5sin θ. y₂ = 5cos (θ + π/6) = 5sin (θ + π/6 + π/2) = 5sin (θ + 2π/3) Phase difference = 2π/3 So the answer is (c) 2π/3.

Two simple harmonic progressive waves have displacements y₁ = 5sin… | MHT CET 2026 (12 May, Shift 1)

Q15MHT CET 2026 · 12 MAY · SHIFT 1Easy

Progressive Wave Equation

Two simple harmonic progressive waves have displacements $y_1 = 5\sin\left(\frac{2\pi x}{\lambda} - \omega t\right)$ and $y_2 = 5\cos\left(\frac{2\pi x}{\lambda} - \omega t + \frac{\pi}{6}\right)$ . The phase difference between the two waves is

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Answer: (c)

Let $\theta = \frac{2\pi x}{\lambda} - \omega t$ . Then $y_1 = 5\sin\theta$ .
$y_2 = 5\cos\left(\theta + \frac{\pi}{6}\right) = 5\sin\left(\theta + \frac{\pi}{6} + \frac{\pi}{2}\right) = 5\sin\left(\theta + \frac{2\pi}{3}\right)$
Phase difference $= \frac{2\pi}{3}$
So the answer is (c) $\frac{2\pi}{3}$ .

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Progressive Wave Equation question from MHT CET 2026 (12 May, Shift 1)

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