Two simple harmonic sound waves travelling in the same direction are given by y₁(x,t) = Asin (0.5π x - 100π t) and y₂(x,t) = Asin (0.46π x - 92π t) The number of times, a stationary listener can hear sound of maximum intensity in one second is (a) 3 (b) 4 (c) 6 (d) 8

Answer: (b). Frequency f = (ω)/(2π): f₁ = (100π)/(2π) = 50 Hz, f₂ = (92π)/(2π) = 46 Hz Beat frequency = f₁ - f₂ = 4 Hz, i.e. 4 maxima per second So the answer is (b) 4.

Two simple harmonic sound waves travelling in the same direction are… | MHT CET 2026 (19 May, Shift 1)

Q1MHT CET 2026 · 19 MAY · SHIFT 1Easy

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Two simple harmonic sound waves travelling in the same direction are given by $y_1(x,t) = A\sin(0.5\pi x - 100\pi t)$ and $y_2(x,t) = A\sin(0.46\pi x - 92\pi t)$

The number of times, a stationary listener can hear sound of maximum intensity in one second is

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Answer: (b)

Frequency $f = \frac{\omega}{2\pi}$ : $f_1 = \frac{100\pi}{2\pi} = 50\text{ Hz}$ , $f_2 = \frac{92\pi}{2\pi} = 46\text{ Hz}$
Beat frequency $= f_1 - f_2 = 4\text{ Hz}$ , i.e. 4 maxima per second
So the answer is (b) $4$ .

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