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MHT CET 2026 (15 May, Shift 1) · Simple Pendulum

Simple Pendulum question from MHT CET 2026 (15 May, Shift 1)

Q12MHT CET 2026 · 15 MAY · SHIFT 1Medium

Simple Pendulum

Two simple pendulums, A of mass $M_1$ and length $L_1$ , and B of mass $M_2$ and length $L_2.\ M_1 = M_2$ and $L_1 = 2L_2$ . If vibrational energies of both are same then which one of the following is correct?

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Answer: (b)

Energy of a pendulum: $E = \frac{1}{2}m\omega^2A^2 = \frac{mgA^2}{2L}$ .
Same $E$ and $m$ : $A^2 \propto L$ .
$L_1 = 2L_2 \Rightarrow A_A = \sqrt{2}A_B$ , so B has the smaller amplitude.
So the answer is (b).

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