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MHT CET 2026 (15 May, Shift 2) · Simple Pendulum

Simple Pendulum question from MHT CET 2026 (15 May, Shift 2)

Q8MHT CET 2026 · 15 MAY · SHIFT 2Medium

Simple Pendulum

Two simple pendulums having lengths ℓ1\ell_1 and ℓ2\ell_2 with negligible string mass undergo angular displacement θ1\theta_1 and θ2\theta_2 from their mean positions respectively. If the angular acceleration of both pendulums are same, then which equation is correct?

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Answer: (d)

  1. For a simple pendulum, angular acceleration α=−gℓθ\alpha = -\frac{g}{\ell}\theta.
  2. Equal α\alpha: θ1ℓ1=θ2ℓ2\frac{\theta_1}{\ell_1} = \frac{\theta_2}{\ell_2}
  3. θ1ℓ2=θ2ℓ1\theta_1\ell_2 = \theta_2\ell_1
  4. So the answer is (d).
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