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NEET 1998 (AIPMT) · Simple Pendulum

Simple Pendulum question from NEET 1998 (AIPMT)

Q87NEET 1998 · AIPMTEasy

Simple Pendulum

Two simple pendulums of length $0.5\text{ m}$ and $2.0\text{ m}$ respectively are given small linear displacement in one direction at the same time. They will again be in the same phase when the pendulum of shorter length has completed oscillations

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Answer: (c)

$T \propto \sqrt{l}$ : $\frac{T_{long}}{T_{short}} = \sqrt{\frac{2.0}{0.5}} = 2$
They are in phase again when $n\,T_{short} = m\,T_{long}$ for the smallest integers: $n = 2$ , $m = 1$ .
So the answer is (c) 2.

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