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JEE Main 2013 (9 Apr, Shift 1) · Simple Pendulum

Simple Pendulum question from JEE Main 2013 (9 Apr, Shift 1)

Q79JEE Main 2013 · 9 APR · SHIFT 1Easy

Simple Pendulum

Two simple pendulums of length 1 m and 4 m respectively are both given small displacement in the same direction at the same instant. They will be again in phase after the shorter pendulum has completed number of oscillations equal to:

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Answer: (a)

$\frac{T_{long}}{T_{short}} = \sqrt{\frac{4}{1}} = 2$
In the time the longer pendulum makes 1 oscillation, the shorter makes 2, and they are in phase again.
So the answer is (a) 2.

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