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JEE Main 2018 (16 Apr, Shift 1) · Beats

Beats question from JEE Main 2018 (16 Apr, Shift 1)

Q58JEE Main 2018 · 16 APR · SHIFT 1Easy

Beats

Two sitar strings, A and B, playing the note 'Dha' are slightly out of tune and produce beats of frequency 5 Hz. The tension of the string B s slightly increased and the beat frequency is found to decrease by 3Hz. If the frequency of A is 425 Hz, the original frequency of B is:

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Answer: (b)

  1. fB=425±5=430f_B = 425 \pm 5 = 430 or 420 Hz420\text{ Hz}.
  2. Increasing tension raises fBf_B, and the beats fall to 5−3=2 Hz5 - 3 = 2\text{ Hz}.
  3. So fB<425f_B < 425: 420→423 Hz420 \to 423\text{ Hz}.
  4. So the answer is (b) 420 Hz.
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