Physics Circle home Student Login

Home›Chapters›Mechanical Properties of Solids PYQs›Shear Modulus & Poisson's Ratio›Question 4

JEE Main 2025 (4 Apr, Shift 1) · Shear Modulus & Poisson's Ratio

Shear Modulus & Poisson's Ratio question from JEE Main 2025 (4 Apr, Shift 1)

Q4JEE Main 2025 · 4 APR · SHIFT 1Medium

Shear Modulus & Poisson's Ratio

Two slabs with square cross section of different materials (1,2)(1, 2) with equal sides (l)(l) and thickness d1d_1 and d2d_2 such that d2=2d1d_2 = 2d_1 and l>d2l > d_2. Considering lower edges of these slabs are fixed to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is θ2=2θ1\theta_2 = 2\theta_1. If the shear moduli of material 1 is 4×109 N/m24 \times 10^{9}\text{ N/m}^2, then shear moduli of material 2 is x×109 N/m2x \times 10^{9}\text{ N/m}^2, where value of xx is ________.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 1

  1. Force on the narrow face of area A=ldA = l d: θ=FG l d\theta = \frac{F}{G\,l\,d}.
  2. θ2θ1=G1d1G2d2⇒2=G12G2\frac{\theta_2}{\theta_1} = \frac{G_1 d_1}{G_2 d_2} \Rightarrow 2 = \frac{G_1}{2G_2}
  3. G2=G14=4×1094=1×109 N/m2G_2 = \frac{G_1}{4} = \frac{4\times10^{9}}{4} = 1\times10^{9}\ \text{N/m}^2
  4. So x=1x = 1.
Report a mistake

More questions on Shear Modulus & Poisson's Ratio