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JEE Main 2024 (8 Apr, Shift 2) · Diffraction at a Single Slit

Diffraction at a Single Slit question from JEE Main 2024 (8 Apr, Shift 2)

Q41JEE Main 2024 · 8 APR · SHIFT 2Medium

Diffraction at a Single Slit

Two slits are $1\text{ mm}$ apart and the screen is located $1\text{ m}$ away from the slits. A light of wavelength $500\text{ nm}$ is used. The width of each slit to obtain 10 maxima of the double slit pattern within the central maximum of the single slit pattern is __________ $\times 10^{-4}\text{ m}$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 2

Central maximum width $\dfrac{2\lambda D}{a}$ holds 10 fringes of width $\dfrac{\lambda D}{d}$ .
$a = \dfrac{2d}{10} = \dfrac{2 \times 10^{-3}}{10} = 2 \times 10^{-4}$ m
So the answer is $2$ .

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