Two slits in Young's double slit experiment are 1.5 mm apart and the screen is placed at a distance of 1 m from the slits. If the wavelength of light used is 600 × 10⁻⁹ m then the fringe separation is (a) 4 × 10⁻⁵ m (b) 9 × 10⁻⁸ m (c) 4 × 10⁻⁷ m (d) 4 × 10⁻⁴ m

Answer: (d). β = (λ D)/(d) = 600×10⁻⁹× 11.5×10⁻³ β = 4×10⁻⁴ m, so the answer is (d).

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YDSE: Fringe Width & Fringe Positions

Two slits in Young's double slit experiment are $1.5\text{ mm}$ apart and the screen is placed at a distance of $1\text{ m}$ from the slits. If the wavelength of light used is $600 \times 10^{-9}\text{ m}$ then the fringe separation is

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Answer: (d)

$\beta = \frac{\lambda D}{d} = \frac{600\times10^{-9}\times 1}{1.5\times10^{-3}}$
$\beta = 4\times10^{-4}\text{ m}$ , so the answer is (d).

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