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JEE Main 2026 (23 Jan, Shift 1) · Angular Momentum & its Conservation

Angular Momentum & its Conservation question from JEE Main 2026 (23 Jan, Shift 1)

Q8JEE Main 2026 · 23 JAN · SHIFT 1Medium

Angular Momentum & its Conservation

Two small balls with masses $m$ and 2 m are attached to both ends of a rigid rod of length $d$ and negligible mass. If angular momentum of this system is $L$ about an axis (A) passing through its centre of mass and perpendicular to the rod then angular velocity of the system about $A$ is:

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Answer: (b)

CM is $\frac{2d}{3}$ from $m$ and $\frac{d}{3}$ from $2m$ .
$I=m\frac{4d^2}{9}+2m\frac{d^2}{9}=\frac{2md^2}{3}$
$\omega=\frac{L}{I}=\frac{3L}{2md^2}$
So the answer is (b) $\frac32\frac{L}{md^2}$ .

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