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MHT CET 2026 (13 Apr, Shift 1) · Splitting & Merging of Drops

Splitting & Merging of Drops question from MHT CET 2026 (13 Apr, Shift 1)

Q12MHT CET 2026 · 13 APR · SHIFT 1Medium

Splitting & Merging of Drops

Two small drops of liquid of same radius coalesce to form a big drop. The ratio of the total surface energies after and before the change is

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Answer: (c)

  1. R=21/3rR = 2^{1/3} r (volume conserved).
  2. EafterEbefore=4π22/3r2T2⋅4πr2T=22/3−1=2−1/3\frac{E_{after}}{E_{before}} = \frac{4\pi 2^{2/3} r^2 T}{2 \cdot 4\pi r^2 T} = 2^{2/3 - 1} = 2^{-1/3}
  3. So the answer is (c) 2−1/3:12^{-1/3} : 1.
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