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JEE Main 2025 (22 Jan, Shift 1) · Excess Pressure: Drops & Bubbles

Excess Pressure: Drops & Bubbles question from JEE Main 2025 (22 Jan, Shift 1)

Q22JEE Main 2025 · 22 JAN · SHIFT 1Medium

Excess Pressure: Drops & Bubbles

Two soap bubbles of radius 2 cm and 4 cm, respectively, are in contact with each other. The radius of curvature of the common surface, in cm, is _________.

Numerical answer type. Work it out, then open the answer.

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Answer: 4

Common surface: $\frac{1}{r} = \frac{1}{r_1} - \frac{1}{r_2}$ (from $\frac{4T}{r} = \frac{4T}{r_1} - \frac{4T}{r_2}$ ).
$\frac{1}{r} = \frac{1}{2} - \frac{1}{4} = \frac{1}{4}$
Radius of curvature $r = 4\text{ cm}$

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