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MHT CET 2024 (15 May, Shift 1) · Self-Inductance & Energy

Self-Inductance & Energy question from MHT CET 2024 (15 May, Shift 1)

Q47MHT CET 2024 · 15 MAY · SHIFT 1Medium

Self-Inductance & Energy

Two solenoids of equal number of turns have their lengths as well as radii in the same ratio 1:31 : 3. The ratio of their self inductance will be

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Answer: (a)

  1. L=μ0N2πr2l∝r2lL = \dfrac{\mu_0 N^2 \pi r^2}{l} \propto \dfrac{r^2}{l} for equal NN.
  2. L1L2=(1/3)21/3=13\dfrac{L_1}{L_2} = \dfrac{(1/3)^2}{1/3} = \dfrac{1}{3}
  3. So the answer is (a) 1:31 : 3.
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