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NEET 2020 (Phase 2) · Ohm's Law, Resistivity & Temperature

Ohm's Law, Resistivity & Temperature question from NEET 2020 (Phase 2)

Q37NEET 2020 · PHASE 2Easy

Ohm's Law, Resistivity & Temperature

Two solid conductors are made up of same material, have same length and same resistance. One of them has a circular cross section of area A1A_1 and the other one has a square cross section of area A2A_2. The ratio A1/A2A_1/A_2 is

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Answer: (c)

  1. R=ρlA⇒A=ρlRR = \dfrac{\rho l}{A} \Rightarrow A = \dfrac{\rho l}{R}
  2. Same ρ\rho, same ll and same RR, so the areas are equal whatever the shape.
  3. A1/A2=1A_1 / A_2 = 1
  4. So the answer is (c) 11.
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