Two sound waves each of wavelength λ and same amplitude A interfere at point Q. If the path difference is (λ)/(4), the amplitude of the resultant wave at point Q is [sin π/2 = 1, cos π/2 = 0] (a) A (b) √(2)A (c) 3A (d) √(3)A

Answer: (b). Phase difference φ = (2π)/(λ) × (λ)/(4) = π/2. AR = √(A² + A² + 2A²cos π/2) = √(2)A. So the answer is (b) √(2)A.

Two sound waves each of wavelength λ and same amplitude A interfere… | MHT CET 2026 (20 Apr, Shift 2)

Q3MHT CET 2026 · 20 APR · SHIFT 2Medium

Reflection, Superposition & Interference

Two sound waves each of wavelength $\lambda$ and same amplitude $A$ interfere at point $Q$ . If the path difference is $\frac{\lambda}{4}$ , the amplitude of the resultant wave at point $Q$ is $\left[\sin\frac{\pi}{2} = 1, \cos\frac{\pi}{2} = 0\right]$

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Answer: (b)

Phase difference $\phi = \frac{2\pi}{\lambda} \times \frac{\lambda}{4} = \frac{\pi}{2}$ .
$A_R = \sqrt{A^2 + A^2 + 2A^2\cos\frac{\pi}{2}} = \sqrt{2}A$ .
So the answer is (b) $\sqrt{2}A$ .

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Reflection, Superposition & Interference question from MHT CET 2026 (20 Apr, Shift 2)

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