Two sound waves having same amplitude ' A ' and angular frequency ' ω ' but having a phase difference of (π/2)c are superimposed then the maximum amplitude of the resultant wave is (a) A/√(2) (b) A/2 (c) √(2)A (d) 2A

Answer: (c). AR = √(A² + A² + 2A²cos φ) φ = π/2 ⇒ cos φ = 0, so AR = √(2)A So the answer is (c) √(2)A.

Two sound waves having same amplitude ' A ' and angular frequency ' ω… | MHT CET 2024 (9 May, Shift 1)

Q8MHT CET 2024 · 9 MAY · SHIFT 1Easy

Reflection, Superposition & Interference

Two sound waves having same amplitude ' $A$ ' and angular frequency ' $\omega$ ' but having a phase difference of $\left(\frac{\pi}{2}\right)^{c}$ are superimposed then the maximum amplitude of the resultant wave is

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Answer: (c)

$A_R = \sqrt{A^2 + A^2 + 2A^2\cos\phi}$
$\phi = \frac{\pi}{2} \Rightarrow \cos\phi = 0$ , so $A_R = \sqrt{2}A$
So the answer is (c) $\sqrt{2}A$ .

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Reflection, Superposition & Interference question from MHT CET 2024 (9 May, Shift 1)

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