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NEET 2006 (AIPMT) · Beats

Beats question from NEET 2006 (AIPMT)

Q69NEET 2006 · AIPMTEasy

Beats

Two sound waves with wavelengths 5.0 m and 5.5. m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second.

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Answer: (a)

$f = \frac{v}{\lambda}$ : $f_1 = \frac{330}{5.0} = 66\text{ Hz}$ , $f_2 = \frac{330}{5.5} = 60\text{ Hz}$
Beats per second $= 66 - 60 = 6$
So the answer is (a) 6.

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