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MHT CET 2023 (10 May, Shift 1) · YDSE: Fringe Width & Fringe Positions

YDSE: Fringe Width & Fringe Positions question from MHT CET 2023 (10 May, Shift 1)

Q38MHT CET 2023 · 10 MAY · SHIFT 1Medium

YDSE: Fringe Width & Fringe Positions

Two sources of light 0.6 mm0.6\text{ mm} apart and screen is placed at a distance of 1.2 m1.2\text{ m} from them. A light of wavelength 6000 A˚6000\ \text{\AA} used. Then the phase difference between the two light waves interfering on the screen at a point at a distance 3 mm3\text{ mm} from central bright band is

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Answer: (d)

  1. Path difference Δx=ydD=3×10−3×0.6×10−31.2=1.5×10−6\Delta x = \frac{yd}{D} = \frac{3\times10^{-3}\times0.6\times10^{-3}}{1.2} = 1.5\times10^{-6} m.
  2. Phase difference ϕ=2πλΔx=2π×1.5×10−66×10−7=5π\phi = \frac{2\pi}{\lambda}\Delta x = \frac{2\pi\times1.5\times10^{-6}}{6\times10^{-7}} = 5\pi
  3. So the answer is (d) 5π5\pi radian.
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