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JEE Main 2024 (29 Jan, Shift 2) · Photons: Energy, Momentum & Radiation Pressure

Photons: Energy, Momentum & Radiation Pressure question from JEE Main 2024 (29 Jan, Shift 2)

Q14JEE Main 2024 · 29 JAN · SHIFT 2Easy

Photons: Energy, Momentum & Radiation Pressure

Two sources of light emit with a power of 200 W200\text{ W}. The ratio of number of photons of visible light emitted by each source having wavelengths 300 nm300\text{ nm} and 500 nm500\text{ nm} respectively, will be:

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Answer: (b)

  1. n=Pλhcn = \frac{P\lambda}{hc}, so for equal power n∝λn \propto \lambda.
  2. n1n2=300500=35\frac{n_1}{n_2} = \frac{300}{500} = \frac{3}{5}
  3. So the answer is (b) 3:53 : 5.
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