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MHT CET 2026 (20 Apr, Shift 2) · Comparing Two Projectiles

Comparing Two Projectiles question from MHT CET 2026 (20 Apr, Shift 2)

Q5MHT CET 2026 · 20 APR · SHIFT 2Medium

Comparing Two Projectiles

Two spheres are projected at angles 30∘30^\circ and 45∘45^\circ with the horizontal. The maximum height reached by both is same. The ratio of their initial velocities is, (sin⁡45∘=12,sin⁡30∘=0.5)\left(\sin 45^\circ = \frac{1}{\sqrt{2}}, \sin 30^\circ = 0.5\right)

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Answer: (b)

  1. Equal H=u2sin⁡2θ2gH = \frac{u^2\sin^2\theta}{2g} means u1sin⁡30∘=u2sin⁡45∘u_1\sin 30^\circ = u_2\sin 45^\circ.
  2. u1u2=sin⁡45∘sin⁡30∘=1/21/2=2\frac{u_1}{u_2} = \frac{\sin 45^\circ}{\sin 30^\circ} = \frac{1/\sqrt{2}}{1/2} = \sqrt{2}
  3. So the answer is (b) 2:1\sqrt{2} : 1.
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