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MHT CET 2025 (20 Apr, Shift 1) · Moment of Inertia & Radius of Gyration

Moment of Inertia & Radius of Gyration question from MHT CET 2025 (20 Apr, Shift 1)

Q46MHT CET 2025 · 20 APR · SHIFT 1Medium

Moment of Inertia & Radius of Gyration

Two spheres each of mass MM and radius RR are connected with a massless rod of length 4 R. The moment of inertia of the system about an axis passing through the centre of one of the spheres and perpendicular to the rod will be

Figure

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Answer: (b)

  1. Sphere on the axis: 25MR2\frac{2}{5}MR^2.
  2. Other sphere, centre at 4R4R: 25MR2+M(4R)2\frac{2}{5}MR^2 + M(4R)^2.
  3. I=45MR2+16MR2=845MR2I = \frac{4}{5}MR^2 + 16MR^2 = \frac{84}{5}MR^2, so the answer is (b).
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