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MHT CET 2024 (11 May, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2024 (11 May, Shift 1)

Q60MHT CET 2024 · 11 MAY · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

Two spheres S1S_1 and S2S_2 have same radii but temperatures T1T_1 and T2T_2 respectively. Their emissive power is same and emissivity in the ratio 1:4. Then the ratio T1:T2T_1 : T_2 is

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Answer: (b)

  1. Same emissive power: e1T14=e2T24e_1 T_1^4 = e_2 T_2^4.
  2. (T1T2)4=e2e1=4\left(\dfrac{T_1}{T_2}\right)^4 = \dfrac{e_2}{e_1} = 4
  3. T1T2=41/4=2\dfrac{T_1}{T_2} = 4^{1/4} = \sqrt{2}
  4. So the answer is (b) 2:1\sqrt{2} : 1.
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