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MHT CET 2025 (23 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2025 (23 Apr, Shift 1)

Q51MHT CET 2025 · 23 APR · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

Two spherical black bodies have radii ' R1R_1 ' and ' R2R_2 '. Their surface temperatures are T1KT_1 K and T2KT_2 K respectively. If they radiate the same power, the ratio R1R2\frac{R_1}{R_2} is

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Answer: (d)

  1. Power P=4πR2σT4P = 4\pi R^2 \sigma T^4; equal power gives R12T14=R22T24R_1^2 T_1^4 = R_2^2 T_2^4.
  2. R1R2=(T2T1)2\dfrac{R_1}{R_2} = \left(\dfrac{T_2}{T_1}\right)^2
  3. So the answer is (d).
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