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MHT CET 2024 (3 May, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2024 (3 May, Shift 1)

Q65MHT CET 2024 · 3 MAY · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

Two spherical black bodies of radii ' R1R_1 ' and ' R2R_2 ' and with surface temperature ' T1T_1 ' and ' T2T_2 ' respectively radiate the same power. The ratio of ' R1R_1 ' to ' R2R_2 ' will be

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Answer: (b)

  1. Power P=4πR2σT4P = 4\pi R^2 \sigma T^4; equal power gives R12T14=R22T24R_1^2 T_1^4 = R_2^2 T_2^4.
  2. R1R2=(T2T1)2\dfrac{R_1}{R_2} = \left(\dfrac{T_2}{T_1}\right)^2
  3. So the answer is (b).
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