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MHT CET 2026 (18 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2026 (18 Apr, Shift 1)

Q22MHT CET 2026 · 18 APR · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

Two spherical black bodies of radii R1R_1 and R2R_2 having surface temperature T1T_1 and T2T_2 respectively, radiate the same power. The ratio of R1R_1 to R2R_2 will be

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Answer: (c)

  1. Power P=4πR2σT4P = 4\pi R^2 \sigma T^4; equal power gives R12T14=R22T24R_1^2 T_1^4 = R_2^2 T_2^4.
  2. R1R2=(T2T1)2\dfrac{R_1}{R_2} = \left(\dfrac{T_2}{T_1}\right)^2
  3. So the answer is (c).
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