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MHT CET 2020 (16 Oct, Shift 2) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2020 (16 Oct, Shift 2)

Q97MHT CET 2020 · 16 OCT · SHIFT 2Medium

Thermal Radiation: Black Body, Stefan & Wien

Two spherical black bodies of radius r1r_1 and r2r_2 with surface temperature T1T_1 and T2T_2 respectively, radiate same power, then r1:r2r_1 : r_2 is

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Answer: (b)

  1. P∝r2T4P \propto r^2 T^4; equal power gives r12T14=r22T24r_1^2 T_1^4 = r_2^2 T_2^4.
  2. r1r2=(T2T1)2\frac{r_1}{r_2} = \left(\frac{T_2}{T_1}\right)^2
  3. So the answer is (b).
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