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NEET 2015 (AIPMT, Cancelled Paper) · Motion of Centre of Mass

Motion of Centre of Mass question from NEET 2015 (AIPMT, Cancelled Paper)

Q8NEET 2015 · AIPMT · CANCELLED PAPERMedium

Motion of Centre of Mass

Two spherical bodies of mass M and 5M and radii R and 2R are released in free space with initial separation between their centres equal to 12R. If they attract each other due to gravitational force only, then the distance covered by the smaller body before collision is:

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Answer: (a)

  1. Only mutual gravity acts, so the CM stays fixed; distances moved are inversely proportional to masses.
  2. They touch when the centres are R+2R=3RR + 2R = 3R apart, so the gap closed is 12R−3R=9R12R - 3R = 9R.
  3. Smaller body: d=5MM+5M⋅9R=56⋅9R=7.5Rd = \frac{5M}{M+5M}\cdot 9R = \frac{5}{6}\cdot 9R = 7.5R
  4. So the answer is (a) 7.5R7.5R.
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