Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Potential & Equipotentials›Question 124

JEE Main 2006 (AIEEE) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from JEE Main 2006 (AIEEE)

Q124JEE Main 2006 · AIEEEMedium

Electric Potential & Equipotentials

Two spherical conductors AA and BB of radii 1 mm1\text{ mm} and 2 mm2\text{ mm} are separated by a distance of 5 cm5\text{ cm} and are uniformly charged. If the spheres are connected by a conducting wire then in equilibrium condition, the ratio of the magnitude of the electric fields at the surfaces of spheres AA and BB is

Show answer and solution

Answer: (c)

  1. Connected spheres are at equal potential, so E=Vr∝1rE = \frac{V}{r} \propto \frac{1}{r}.
  2. EAEB=rBrA=21\frac{E_A}{E_B} = \frac{r_B}{r_A} = \frac{2}{1}
  3. So the answer is (c) 2:12 : 1.
Report a mistake

More questions on Electric Potential & Equipotentials