Two spherical conductors B and C having equal radii and carrying… | JEE Main 2004 (AIEEE)

Q77JEE Main 2004 · AIEEEMedium

Electric Charge & Coulomb's Law

Two spherical conductors $B$ and $C$ having equal radii and carrying equal charges on them repel each other with a force $F$ when kept apart at some distance. A third spherical conductor having same radius as that of $B$ but uncharged is brought in contact with $B,$ then brought in contact with $C$ and finally removed away from both. The new force of repulsion between $B$ and $C$ is

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Answer: (d)

Equal radii, so charge is shared equally on contact.
After touching B: $B = \dfrac{q}{2}$ . After touching C: $C = \dfrac{q/2 + q}{2} = \dfrac{3q}{4}$ .
$F' = \dfrac{k(q/2)(3q/4)}{r^2} = \dfrac{3F}{8}$
So the answer is (d) $3F/8$ .

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