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NEET 2001 (AIPMT) · Spring & Elastic Energy

Spring & Elastic Energy question from NEET 2001 (AIPMT)

Q34NEET 2001 · AIPMTEasy

Spring & Elastic Energy

Two springs A and B having spring constant KA and KB (KA = 2KB) are stretched by applying force of equal magnitude. If energy stored in spring A is EA then energy stored in B will be

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Answer: (a)

For the same force $F = kx \Rightarrow x = F/k$ , so $E = \frac{1}{2}kx^2 = \frac{F^2}{2k}$ .
$E \propto \frac{1}{k}$ : $\frac{E_B}{E_A} = \frac{k_A}{k_B} = 2$
So the answer is (a) $2E_A$ .

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