Two stars A and B radiate maximum energy at wavelength 3.9 × 10⁻⁷ m and 5.2 × 10⁻⁷ m respectively. The ratio of the temperature of star A to that of star B will be (a) 2: 3 (b) 3: 2 (c) 3: 4 (d) 4: 3

Answer: (d). Wien's law: λm T = b, so T ∝ (1)/(λm). (TA)/(TB) = (λB)/(λA) = 5.2 × 10⁻⁷3.9 × 10⁻⁷ = 4/3 So the answer is (d) 4: 3.

Two stars A and B radiate maximum energy at wavelength 3.9 × 10⁻⁷ m… | MHT CET 2026 (20 Apr, Shift 2)

Q10MHT CET 2026 · 20 APR · SHIFT 2Easy

Thermal Radiation: Black Body, Stefan & Wien

Two stars A and B radiate maximum energy at wavelength $3.9 \times 10^{-7}$ m and $5.2 \times 10^{-7}$ m respectively. The ratio of the temperature of star A to that of star B will be

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Answer: (d)

Wien's law: $\lambda_m T = b$ , so $T \propto \dfrac{1}{\lambda_m}$ .
$\dfrac{T_A}{T_B} = \dfrac{\lambda_B}{\lambda_A} = \dfrac{5.2 \times 10^{-7}}{3.9 \times 10^{-7}} = \dfrac{4}{3}$
So the answer is (d) $4 : 3$ .

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