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MHT CET 2026 (19 Apr, Shift 1) · Centripetal Acceleration & Force

Centripetal Acceleration & Force question from MHT CET 2026 (19 Apr, Shift 1)

Q2MHT CET 2026 · 19 APR · SHIFT 1Medium

Centripetal Acceleration & Force

Two stones of masses mm and 3m3m are whirled in horizontal circles, the heavier one in a radius r3\frac{r}{3} and the lighter one in radius rr. When both the stones experience same centripetal forces, the tangential speed of lighter stone is 'nn' times that of the value of heavier stone. The value of 'nn' is

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Answer: (c)

  1. Equal forces: mv12r=3mv22r/3=9mv22r\frac{m v_1^2}{r} = \frac{3m v_2^2}{r/3} = \frac{9 m v_2^2}{r}.
  2. v12=9v22⇒v1=3v2v_1^2 = 9 v_2^2 \Rightarrow v_1 = 3 v_2
  3. So n=3n = 3. The answer is (c) 33.
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