Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Speed of Waves›Question 9

JEE Main 2026 (21 Jan, Shift 1) · Speed of Waves

Speed of Waves question from JEE Main 2026 (21 Jan, Shift 1)

Q9JEE Main 2026 · 21 JAN · SHIFT 1Difficult

Speed of Waves

Two strings (A,B)(A, B) having linear densities μA=2×10−4 kg/m\mu_A = 2 \times 10^{-4}\text{ kg/m} and, μB=4×10−4 kg/m\mu_B = 4 \times 10^{-4}\text{ kg/m} and lengths LA=2.5 mL_A = 2.5\text{ m} and LB=1.5 mL_B = 1.5\text{ m} respectively are joined. Free ends of AA and BB are tied to two rigid supports CC and DD, respectively creating a tension of 500 N in the wire. Two identical pulses, sent from CC and DD ends, take time t1t_1 and t2t_2, respectively, to reach the joint. The ratio t1/t2t_1/t_2 is:

Show answer and solution

Answer: (b)

  1. t=L/v=Lμ/Tt = L/v = L\sqrt{\mu/T}, same TT for both.
  2. t1t2=LALBμAμB=2.51.512=1.667×0.707\dfrac{t_1}{t_2} = \dfrac{L_A}{L_B}\sqrt{\dfrac{\mu_A}{\mu_B}} = \dfrac{2.5}{1.5}\sqrt{\dfrac{1}{2}} = 1.667 \times 0.707
  3. t1/t2≈1.18t_1/t_2 \approx 1.18
  4. So the answer is (b) 1.18.
Report a mistake

More questions on Speed of Waves