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JEE Main 2025 (7 Apr, Shift 1) · Combination of Lenses

Combination of Lenses question from JEE Main 2025 (7 Apr, Shift 1)

Q12JEE Main 2025 · 7 APR · SHIFT 1Easy

Combination of Lenses

Two thin convex lenses of focal lengths 30 cm and 10 cm are placed coaxially, 10 cm apart. The power of this combination is:

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Answer: (d)

  1. For separated lenses P=P1+P2−dP1P2P = P_1 + P_2 - dP_1P_2 (SI units).
  2. P1=10.3=103 DP_1 = \frac{1}{0.3} = \frac{10}{3}\text{ D}, P2=10.1=10 DP_2 = \frac{1}{0.1} = 10\text{ D}, d=0.1 md = 0.1\text{ m}
  3. P=103+10−0.1×103×10=10 DP = \frac{10}{3} + 10 - 0.1 \times \frac{10}{3} \times 10 = 10\text{ D}
  4. So the answer is (d) 10 D.
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