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NEET 2014 (AIPMT) · Dielectrics

Dielectrics question from NEET 2014 (AIPMT)

Q105NEET 2014 · AIPMTMedium

Dielectrics

Two thin dielectric slabs of dielectric constants K1 and K2(K1 < K2) are inserted between plates of a parallel plate capacitor, as shown in the figure. The variation of electric field E between the plates with distance d as measured from plate P is correctly shown by

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Answer: (c)

In air between the plates $E_0=\frac{\sigma}{\epsilon_0}$ ; inside a slab $E=\frac{E_0}{K}$ .
$K_1<K_2$ , so the dip in the $K_1$ slab is smaller than the dip in the $K_2$ slab.
Between the slabs and next to the plates $E=E_0$ ; beyond plate Q, $E=0$ .
So the answer is (c).

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