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JEE Main 2005 (AIEEE) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from JEE Main 2005 (AIEEE)

Q66JEE Main 2005 · AIEEEEasy

Force on Current-Carrying Conductors

Two thin, long, parallel wires, separated by a distance ′d′'d' carry a current of ′i′ A'i'\ A in the same direction. They will

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Answer: (b)

  1. Currents in the same direction attract.
  2. Fl=μ0i⋅i2πd=μ0i22πd\frac{F}{l} = \frac{\mu_0 i \cdot i}{2\pi d} = \frac{\mu_0 i^2}{2\pi d}
  3. So the answer is (b) attract with force μ0i2/(2πd)\mu_0 i^2/(2\pi d) (per unit length).
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