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MHT CET 2026 (19 Apr, Shift 1) · Force on Current-Carrying Conductors

Force on Current-Carrying Conductors question from MHT CET 2026 (19 Apr, Shift 1)

Q3MHT CET 2026 · 19 APR · SHIFT 1Easy

Force on Current-Carrying Conductors

Two thin long parallel wires, $W_1$ and $W_2$ separated by distance ' $a$ ', carry currents $i$ and $3i$ respectively in the same direction. The magnitude of the force per unit length exerted by wire $W_1$ on wire $W_2$ is

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Answer: (c)

$\dfrac{F}{L} = \dfrac{\mu_0 I_1 I_2}{2\pi a}$
$\dfrac{F}{L} = \dfrac{\mu_0 (i)(3i)}{2\pi a} = \dfrac{3\mu_0 i^2}{2\pi a}$
So the answer is (c).

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