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JEE Main 2021 (31 Aug, Shift 2) · Heat Conduction

Heat Conduction question from JEE Main 2021 (31 Aug, Shift 2)

Q42JEE Main 2021 · 31 AUG · SHIFT 2Difficult

Heat Conduction

Two thin metallic spherical shells of radii r1 and r2 (r1 < r2) are placed with their centres coinciding. A material of thermal conductivity K is filled in the space between the shells. The inner shell is maintained at temperature θ\theta1 and the outer shell at temperature θ2(θ\theta_2 (\theta1 < θ\theta2). The rate at which heat flows radially through the material is :-

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Answer: (a)

  1. Thin spherical shell: H=K(4πr2)dθdrH = K(4\pi r^2)\dfrac{d\theta}{dr}, constant through all shells.
  2. Integrate from r1r_1 to r2r_2: H(1r1−1r2)=4πK(θ2−θ1)H\left(\dfrac{1}{r_1}-\dfrac{1}{r_2}\right) = 4\pi K(\theta_2-\theta_1)
  3. H=4πKr1r2(θ2−θ1)r2−r1H = \dfrac{4\pi K r_1 r_2(\theta_2-\theta_1)}{r_2-r_1}
  4. So the answer is (a).
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