Two transparent media A and B are separated by a plane boundary. The speed of light in those media are 1.5 × 108 m/s and 2.0 × 108 m/s, respectively. The critical angle for a ray of light for these two media is (a) sin ⁻¹ (0.500) (b) sin ⁻¹ (0.750) (c) tan ⁻¹ (0.500) (d) tan ⁻¹ (0.750)

Answer: (b). sin C = (μB)/(μA) = (vA)/(vB) (from slower A to faster B). sin C = (1.5 × 10⁸)/(2.0 × 10⁸) = 0.750 So the answer is (b) sin ⁻¹(0.750).

Two transparent media A and B are separated by a plane boundary. The… | NEET 2022 (Phase 1)

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Total Internal Reflection

Two transparent media A and B are separated by a plane boundary. The speed of light in those media are 1.5 $\times$ 108 m/s and 2.0 $\times$ 108 m/s, respectively. The critical angle for a ray of light for these two media is

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Answer: (b)

$\sin C = \frac{\mu_B}{\mu_A} = \frac{v_A}{v_B}$ (from slower A to faster B).
$\sin C = \frac{1.5 \times 10^8}{2.0 \times 10^8} = 0.750$
So the answer is (b) $\sin^{-1}(0.750)$ .

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