Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Stationary Waves & Vibrating Strings›Question 72

JEE Main 2022 (24 Jun, Shift 2) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from JEE Main 2022 (24 Jun, Shift 2)

Q72JEE Main 2022 · 24 JUN · SHIFT 2Easy

Stationary Waves & Vibrating Strings

Two travelling waves of equal amplitudes and equal frequencies move in opposite directions along a string. They interfere to produce a stationary wave whose equation is given by y=(10cos⁡πxsin⁡2πtT)y = \left(10\cos\pi x\sin\frac{2\pi t}{T}\right) cm

The amplitude of the particle at x=43x = \frac{4}{3} cm will be ___________ cm.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 5

  1. Amplitude at xx: ∣10cos⁡πx∣|10\cos\pi x|.
  2. At x=43x = \frac{4}{3}: 10∣cos⁡4π3∣=10×12=5 cm10\left|\cos\frac{4\pi}{3}\right| = 10 \times \frac{1}{2} = 5\text{ cm}.
Report a mistake

More questions on Stationary Waves & Vibrating Strings