Physics Circle home Student Login

Home›Chapters›Wave Motion PYQs›Stationary Waves & Vibrating Strings›Question 75

JEE Main 2021 (26 Aug, Shift 1) · Stationary Waves & Vibrating Strings

Stationary Waves & Vibrating Strings question from JEE Main 2021 (26 Aug, Shift 1)

Q75JEE Main 2021 · 26 AUG · SHIFT 1Easy

Stationary Waves & Vibrating Strings

Two travelling waves produce a standing wave represented by equation,

y = 1.0 mm cos(1.57 cm−1{}^{-1}) x sin(78.5 s−1{}^{-1})t.

The node closest to the origin in the region x > 0 will be at x = .............. cm.

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 1

  1. Nodes where cos⁡(1.57x)=0\cos(1.57x) = 0, i.e. 1.57x=π21.57x = \frac{\pi}{2} for the first node.
  2. x=1.571.57=1 cmx = \frac{1.57}{1.57} = 1\text{ cm}.
Report a mistake

More questions on Stationary Waves & Vibrating Strings